2x^2-10x+(k-5)=0

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Solution for 2x^2-10x+(k-5)=0 equation:


Simplifying
2x2 + -10x + (k + -5) = 0

Reorder the terms:
2x2 + -10x + (-5 + k) = 0

Remove parenthesis around (-5 + k)
2x2 + -10x + -5 + k = 0

Reorder the terms:
-5 + k + -10x + 2x2 = 0

Solving
-5 + k + -10x + 2x2 = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + k + -10x + 5 + 2x2 = 0 + 5

Reorder the terms:
-5 + 5 + k + -10x + 2x2 = 0 + 5

Combine like terms: -5 + 5 = 0
0 + k + -10x + 2x2 = 0 + 5
k + -10x + 2x2 = 0 + 5

Combine like terms: 0 + 5 = 5
k + -10x + 2x2 = 5

Add '10x' to each side of the equation.
k + -10x + 10x + 2x2 = 5 + 10x

Combine like terms: -10x + 10x = 0
k + 0 + 2x2 = 5 + 10x
k + 2x2 = 5 + 10x

Add '-2x2' to each side of the equation.
k + 2x2 + -2x2 = 5 + 10x + -2x2

Combine like terms: 2x2 + -2x2 = 0
k + 0 = 5 + 10x + -2x2
k = 5 + 10x + -2x2

Simplifying
k = 5 + 10x + -2x2

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